Eh, taking shots of liquor works when your to drunk to mix.
(Tequila=Someone guaranteed to throw up)

(mmm, schnapps)

*sigh* When will people learn to just eat their children...  

My girlfriend has a theory that realtionships should be based of friendships and your boyfriend/girlfriend should be your best friend.

But   also works...

Shouldn't be a problem, last foreign aid was on the 9th.

Managed to dig up this from http://en.allexperts.com/q/Physics-1358/force-chain.htm, hope it helps.

"The problem is that you are only considering the weight of the chain. The table also has to exert an upward force to stop the chain from falling! That can be determined by using the "impulse" form of Newton's 2nd Law F=m*Dv/Dt.
In this case F=v*Dm/Dt Dm is the mass of one little piece of the chain. SInce the chanin has a mass of 2 kg and a length of 1m the mass per unit length of the chain is lambda=mass/length=2kg/m. If you multiply this mass per unit length by the length of a piece of the length of the chain Dl you will get the mass of the little piece.
Dm=lambda*Dl. Newton's 2nd Law then becomes
F=v*Dm/Dt=v*lambda*Dl/Dt where Dl/Dt is the velocity of the chain therefore F=v*lambda*v=v^2*lambda.
Before finishing the problem you need to determine the time t when the chain contacts the table. Do=0, Df=-0.6m, Vo=0m/s, a=-9.8m/s^2, Vf=? and t=?
Using the displacement equation determine the time
Df=1/2*a*t^2+Vo*t+Do
-0.6=1/2*(-9.8)*t^2+0+0 solve for t.
Then use the velocity equation to determine the velocity of the chain link at the time it strikes the table.
Vf=a*t+Vo
Vf=-9.8*t+0 solve for Vf. The magnitude of this velocity is the speed of the chain when it collides with the table.
Use this velocity to calculate the force required to stop the falling chain.  
Finally, the forc exerted by the table will be equal to the sum of the force needed to support the weight of the chain plus the force needed to stop the link of the falling chain."

7.56 N

F=MA
2kg*4.2M/SEC^2

Probably wrong...